case study questions class 8 maths pdf

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CBSE Class 8th Maths Value Based Questions PDF Download

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CBSE Class 8th Maths Value Based Questions are the easiest questions which you see in your question paper and the scoring one all student who attempt it surely get they are just little bit difficult and examine your basic knowledge regarding the particular chapter. Maths Value Based Questions for Class 8th are available here at Free of cost. These questions are expected to be asked in the Class 8th board examination. These Maths Value Based Questions are from complete CBSE Syllabus.

CBSE Class 8th Maths Value Based Questions

Most of these Maths Value Based Questions are quite easy and students need only a basic knowledge of the chapter to answer these questions. Download CBSE Maths Value Based Questions for board examinations. These Maths Value Based Questions are prepared by Directorate of Education, Delhi.

CBSE Maths Value Based Questions Class 8th PDF

The purpose of the Maths Value Based Questions is to make students aware of how basic values are needed in the analysis of different situations and how students require to recognize those values in their daily lives. Some questions are subject related. But even if they are not, that one-minute awareness of what we write about value without any specific preparation is a good step indeed.

CBSE Maths Value Based Questions for Class 8th download here in PDF format. The most CBSE Maths Value Based Questions for annual examination are given here for free of cost. The additional questions for practice the Class 8th exam are collected from various sources. It covers questions asked in previous year examinations.

CBSE Maths Value Based Questions for Class 8th Free PDF

Class 8th books have many questions. These questions are regularly asked in exams in one or other way. Practising such most CBSE Maths Value Based Questions certainly help students to obtain good marks in the examinations. 

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CBSE Sample Papers for Class 8 Maths

CBSE Sample Papers for Class 8 Maths are a perfect trial run for the students through which they can check their exam preparation. They are able to make out where they are committing the mistakes, and thus they can work on those areas. This will improve their overall performance. Practising the CBSE sample papers is an effective way to get rid of exam fear. Solving CBSE Class 8 Sample Papers for Maths can sometimes seem tedious, but it is worth every effort. Solving them will provide a precise simulation of the exam. It gives students a feeling of confidence and frees them from all the anxiety on exam day.

Here we have provided a set of solved sample papers and 5 sets of unsolved CBSE Sample Papers for Class 8 Maths. These papers are designed by the subject experts and are as per the CBSE exam pattern. These papers cover all the important topics of the Syllabus. Students can download the CBSE Class 8 Maths sample papers from the table below.

Solving CBSE Class 8 Maths Sample Papers tests students months of effort and training, it will also give them an idea regarding their preparations. CBSE Class 8 sample papers for Maths serve a lot of benefits, and here are some of the major benefits among many. Students can get the complete study material related to CBSE Class 8 at BYJU’S.

Benefits of Solving the CBSE Class 8 Maths Sample Papers

1) Strengths And Weaknesses

When students solve CBSE sample papers, they get a real status of their preparation. They get to know how well they are prepared for the Maths exam and rate themselves accordingly by solving the latest CBSE sample papers. Also, they experience a gradual improvement in their performance by working on weak areas.

2) Time Management

Students identify the sections that require more time by solving the sample papers. Accordingly, they will speed up their question-solving speed so that they can solve all the questions during the exam.

3) Important Formulas

When students solve the questions, they come across the Maths formulas. By solving the questions, again and again, they get all the important formulas at their fingertips. This saves their time in the exam, and they will quickly solve the paper.

4) Quick Revision

Sample papers consist of important questions that either have appeared in the previous year’s Class 8 Maths exams or are part of the CBSE Class 8 Maths Syllabus . There is no need to go through every page of the NCERT textbook since by solving the Class 8 Sample Papers, students can revise all the major sections in quick succession of time.

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Important Questions for CBSE Class 8 Maths Chapter 11 - Direct and Inverse Proportions

• Class 8 Important Question
• Chapter 13: Direct And Inverse Proportions

CBSE Class 8 Maths Important Questions for Direct and Inverse Proportions - Free PDF Download

Free PDF download of Important Questions with solutions for CBSE Class 8 Maths Chapter 11 - Direct and Inverse Proportions prepared by expert Mathematics teachers from latest edition of CBSE(NCERT) books. Register online for Maths tuition on Vedantu.com to score more marks in your examination.

Vedantu is a platform that provides free (CBSE) NCERT Solution and other study materials for  Subjects like Science, Maths, English will become easy to study if you have access to NCERT Solution for Class 8 Science , Maths solutions and solutions of other subjects.

Download Class 8 Maths NCERT Solutions to help you to revise complete syllabus ans score more marks in your examinations.

Study Important Questions for Class 8 Maths Chapter 11 – Direct and Inverse proportions

Very short answer type questions.

1. If two quantities x and y are in direct proportion with each other, then:

(a) $\dfrac{{\text{x}}}{{\text{y}}}$ remains constant

(b) $x\times y$ remains constant

(c) ${\text{x}}\,{\text{ - }}\,{\text{y}}$ remains constant

(d) None of these

Ans: (a) $\dfrac{{\text{x}}}{{\text{y}}}$ remains constant. 

2. The cost of 5 metres of a particular quality of cloth is Rs.210. Find the cost of 2 metres of cloth of the same type.

(d) Rs. 100

Ans: Cost of 5 metre cloth = Rs. 210

Thus, cost of 2 metre cloth = $\dfrac{{2 \times 210}}{5}\, = \,{\text{Rs}}{\text{.84}}$

3. If X = 5Y, then X and Y vary ______ with each other.

Ans: They are directly proportional.

${\text{X }} \propto {\text{ Y}}$

$\dfrac{{\text{X}}}{{\text{Y}}}\, = \,5$

4. If XY = 10 then X and Y vary _____ with each other.

Ans: Indirectly proportional.

5. Time taken to cover a distance by car and speed of the car are said to be in _______ variation.

Ans: Inversely

${\text{Speed  =  }}\dfrac{{{\text{distance}}}}{{{\text{time}}}}$

${\text{speed }} \propto \,\dfrac{1}{{{\text{time}}}}$

6. In the table state whether x and y vary directly or indirectly.

Ans: Since, as ‘x’ increases, ‘y’ also increases. 

Therefore, ‘x’ and ‘y’ vary directly.

7. If a car covers 80km in 5 litres of petrol, how much distance will it cover in 3 litres of petrol?

Ans: Given: In 5 litres of petrol, distance covered = 80km

Thus, in 1 litre of petrol, distance covered = $\dfrac{{80}}{5} = {\text{ 16km}}$

In, 13 litres of petrol, distance covered = $16\, \times \,13\, = \,{\text{208km}}$

Short  Answer Type Questions                                                         2 Mark

8. If 32 men can reap a field in 15 days. In how many days can 40 men reap the same field?

Ans: This situation is inverse variation (less men, more days)

Let $x=$ men,$y=$ no. of days $x_{1}=32, y_{1}=15$ $x_{2}=40, y_{2}=?$

Formula is $x_1 y_1=x_2 y_2$

$(32)(15)=(40) \mathrm{y} 2$

$\mathrm{y}_{2}=\dfrac{32 \times 15}{40}$

$\mathrm{y}_{2}=12$

Therefore, number of days $=12$

9. If 4 kg potatoes cost Rs. 60. What is the cost of 12kg of potatoes?

Ans: Given: cost of 4 kg potatoes = Rs. 60

Therefore, 1 kg potatoes cost Rs = $\dfrac{{60}}{4} = 15$

Thus, 12kg potatoes cost = $15\, \times \,12\, = \,{\text{Rs}}{\text{.180}}$

10. Find the value of x and y if x : y = 2 : 3 and 2 : x = 1 : 2.

Ans: Given: 2 : x = 1 : 2

$\Rightarrow {\text{ }}\dfrac{2}{{\text{x}}} = \dfrac{1}{2}$

 $\Rightarrow \,{\text{x  =  2}} \times {\text{2}} $

 $\Rightarrow {\text{x = 4}} $

  ${\text{x : y  =  2 : 3}} $

 $ {\text{4 : y  =  2 : 3}} $

  $\dfrac{4}{{\text{y}}}\, = \,\dfrac{2}{3} $

  ${\text{y  =  }}\dfrac{{4 \times 3}}{2} $

  ${\text{y  =  6}} $ 

11. If 2 : 3 = x : 51. Find ‘x’.

Ans: $\dfrac{2}{3}\, = \,\dfrac{{\text{x}}}{{51}} $

   $\Rightarrow \,{\text{x  =  }}\dfrac{{2 \times 51}}{3} $

   $\Rightarrow {\text{x  =  34}} $ 

Short  Answer Type Questions                                                         3 Mark

12. if x and y are in inverse proportion. find the value of a, b and c in the table..

$\mathrm{x} \propto \dfrac{1}{\mathrm{y}} \Rightarrow \mathrm{x_1} \mathrm{y_1}=\mathrm{x_2} \mathrm{y_2}$

$25 \times 3=15 \times \mathrm{a} \Rightarrow \mathrm{a}=\dfrac{75}{15}=5$

$25 \times 3=\mathrm{b} \times 4 \Rightarrow \mathrm{b}=\dfrac{75}{4}=18.75$

$25 \times 3=10 \times \mathrm{c} \Rightarrow \mathrm{c}=\dfrac{75}{10}=7.5$

13. The scale of a map is given as 1 : 80000000. Two places A and B on the map are 3 cm apart. What is the actual distance between A and B? If C and D are at a distance of 3200 km, then find the distance between them on map?

Ans: Given: scale of map = 1 : 80000000

Thus, 1 unit on map shows 80000000 units in the real world.

If A and B are 3 cm apart on map,

Actual distance =

 ${\text{3cm }} \times {\text{ 80000000}} $

  ${\text{ =  240000000}} $

  ${\text{ =  2400 km}} $ 

If C and D are at a distance of 32km apart, then

${\text{3200km  =  3200 }} \times {\text{ 1000 }} \times {\text{ 100cm}} $

  ${\text{ =  320000000 cm}} $ 

Therefore, on the map it should be $ = \,\dfrac{{320000000}}{{80000000}}\, = \,{\text{4cm}}$

14. There are 50 students in a hostel. The food provision for them is for 15 days. How long will their provision last if 5 students leave the group?

Ans: It is inverse variation since no. of students increases as no. of days food provision provided increases.

Let ' $x$ ' be the no. of students And ' $\mathrm{y}$ ' be the number of days 

Given: $\mathrm{x}_{1}=50, \mathrm{y}_{1}=15$

$\mathrm{x}_{2}=50-5=45, \mathrm{y}_{2}=? $

$\mathrm{x_1} \mathrm{y_1}=\mathrm{x_2} \mathrm{y_2}$

$50 \times 15=45 \times \mathrm{y_2}$

$\mathrm{y}_{2}=\dfrac{50 \times 15}{45}$

$\mathrm{y}_{2}=16.66=17$ days

15. A workforce of 210 men with a supervisor can finish a certain piece of work in 5 months. How many extra men must he employ if he want to complete job in just 2 months?

Ans:   Let the extra men employed be ‘x’

Number of men(x):       210           x

Months(y):                         5             2

Since, men hired and time required are inversely proportional, we have

$\mathrm{x_1} \mathrm{y_1}=\mathrm{x_2}\mathrm{y}_{2}$

$210 \times 5=\mathrm{x} \times 2 $

$\mathrm{x}=\dfrac{210 \times 5}{2}=525$

Thus, extra men needed $=525-210=315$.

16. Ranjith has enough money to buy 75 machines worth Rs. 200 each. How many machines can he buy if he gets a discount of Rs.50 on each machines?

Ans: Let the no. of machines he can buy if a discount of Rs. 50 is offered on each machine be ‘x’.

Number of Machines(x):                         75                             x

Price of Each Machine(y):                       200                           150

Since the discount is Rs.50, the cost of each machine will be 200 – 50  = 150.

It is the inverse proportion as if the price of a machine is less, the more machines he can buy.

$75\, \times \,200\, = \,{\text{x}}\, \times {\text{ 150}} $

$\Rightarrow \,{\text{x  =  }}\dfrac{{75\, \times \,200}}{{150}}\, = \,\dfrac{{15000}}{{150}} $

 $\Rightarrow \,{\text{x  =  100}} $ 

17. A worker is paid Rs. 420 for 2 days work. If his total income of the month is Rs. 1750, For how many days did he work?

Ans: It is direct variation. More wages, more days of work.

Let ‘x’ be the amount paid and ‘y’ be the number of days.

Amount paid(x)     :   Rs.420       Rs.1750     

Number of days(y):   12                ?

$\dfrac{\mathrm{x}_1}{\mathrm{y}_1}=\dfrac{\mathrm{x}_2}{\mathrm{y}_2}$

$\dfrac{420}{12}=\dfrac{1750}{\mathrm{y}_2} $

$\mathrm{y}_{2}=\dfrac{1750 \times 12}{420} $

$\mathrm{y}_{2}=50 \text { days }$

18. Abdul takes 75 steps to cover a distance of 50m. How much distance will it cover in 375 steps?

Ans: It is direct variation as the number of steps increases, the distance covered will be more.

Let ‘x’ be the number of steps and ‘y’ be the distance covered.

Number of steps(x):     75      375

Distance covered(y):   50m     ?

$\dfrac{75}{50}=\dfrac{375}{\mathrm{y}_2} $

$\mathrm{y}_{2}=\dfrac{375 \times 50}{75} $

$\mathrm{y}_{2}=250 \mathrm{~m}$

19. If the weights of 8 sheets of paper be 45 grams. How many sheets would weigh $1\dfrac{1}{2}$kg?

Ans: It is direct variation as more number of sheets implies more weight.

Number of sheets(x):   6       ?

Number of hours(y):   45     $1\dfrac{1}{2}$kg = 1500g [1 Kg = 1000g, 1.5Kg = 1500g]

$\dfrac{\mathrm{x}_1}{\mathrm{y}_1}=\dfrac{\mathrm{x}_2}{\mathrm{y}_{2}} $

$\dfrac{6}{45}=\dfrac{\mathrm{x}_2}{1500}$

$\mathrm{x}_{2}=\dfrac{6 \times 1500}{45}$

$\mathrm{x}_{2}=200$

20. 20 pumps can empty a reservoir is 12 hours. In how many hours can 45 such pumps do the same work?

Ans: It is inverse variation as it takes less hours if the number of pumps are more.

Number of pumps(x):   20      45

Number of hours(y):     12       ?

$x_1 y_{1}=x_2 y_2 $

$20 \times 12=45 \times y_2 $

$y_{2}=\dfrac{20 \times 12}{45} $

$y_{2}=5.33=5 \dfrac{1}{3} \text { hours }$

Long  Answer Type Questions                                                                          5 Mark  

21. A water tanker can finish a certain journey in 10 hours at the speed of 38 km/hr. By how much should its speed be increased so that it may take only 8 hours to cover the same distance?

Ans: Given: speed = 38 km/hr, time = 10 hours.

Distance covered = speed $ \times $ time = $38\, \times \,10\, = \,380\,{\text{km}}$

Speed(x)            :     38km/hr          ?

Time taken(y)   :     10 hours        8 hours

It is an inverse variation.

$\mathrm{x}_1 \mathrm{y}_1=\mathrm{x}_2 \mathrm{y}_2 $

$38 \times 10=\mathrm{x}_2 \times 8 $

$\mathrm{x}_{2}=\dfrac{38 \times 10}{8} $

$\mathrm{x}_{2}=47.5 \mathrm{~km} / \mathrm{hr}$

Thus, the speed is increased by $47.5-38=9.5 \mathrm{~km} / \mathrm{hr}$.

22. 1000 children in a hostel had enough food for 28 days. After 4 days, some children were shifted to other hostel. As a result, the food now lasted for 32 days. How many students were shifted?

Ans: Given: 1000 students in a hostel had enough food for 28 days.

Let ‘x’ be the number of students shifted.

Number of students(x):   1000      1000-x

Number of days:                 28           32

It is an inverse variation: as the number of students increases, food remains for less number of days.

${x_1 y_1  =  x_2 y_2} $

$1000\times 28=(1000-x)\times 32 $

$1000-x = \dfrac{1000\times 28}{32}=875 $

$x = 1000-875=125 $ 

Therefore, the number of students shifted = 125.

23. The amount of extension in the length of the elastic string directly varies as the weight hung on it. If a weight of 500 gm produces an extension of 3 cm, then what weight would produce an extension of 36.2 cm. Write the solution in Kg.

Ans: Weight(x)                      :   200gm      7

Extension in length(y) :    3 cm        36.2 cm

It is a direct variation.

$\dfrac{x_1}{y_1}= \dfrac{x_2}{y_2} $

$\dfrac{{200}}{3}\, = \,\dfrac{{{\text{x2}}}}{{36.2}} $

$x_2 = \dfrac{{200\, \times \,36.2}}{3} $

$x_2 = \dfrac{{7240}}{3} $

$x_2 = 2.41kg  $ 

24. Find ‘a’ in the following table when

x, y vary directly

(b)  x, y vary inversely.

when x and y vary directly.

$ \dfrac{x_1}{y_1}= \dfrac{x_2}{y_2} $

$ \dfrac{2}{{10}}\, = \,\dfrac{5}{{\text{a}}} $

 $ {\text{a  =  }}\dfrac{{50}}{2}\, = \,25 $ 

When x and y vary inversely

$ {x_1 y_1  =  x_2 y_2} $

 $ 2\, \times \,10\, = \,5\, \times \,{\text{a}} $

  ${\text{a  =  }}\dfrac{{20}}{5} $

 $ {\text{a  =  4}} $ 

25. Which of the following quantities vary directly or indirectly with each other

Number of pens and their cost

Distance travelled (at constant speed) and petrol used.

Number of men available and time taken to do a job.

Area of land and its price.

wages y and hours of work x.

As pens increase, cost increases – direct variation.

As distance travelled increases, the amount of petrol increases – direct variation.

Number of men decreases, time taken increases – Inverse variation.

Direct variation.

Common Mistakes Students Make While Solving Class 8 Maths Chapter 11 - Direct and Inverse Proportions Problems:

Here are common mistakes students make while solving problems in Class 8 Maths Chapter 11 - Direct and Inverse Proportions:

1. Confusing Direct and Inverse Proportions: Students often mix up the concepts of direct and inverse proportions. It's crucial to grasp when one variable increases with the other (direct) and when it decreases (inverse).

2. Misinterpreting Proportionality Constants: Students sometimes miscalculate or misinterpret the constant of proportionality. Pay attention to its role in maintaining the relationship between variables.

3. Skipping Units in Ratios: Ignoring units while setting up ratios can lead to errors. Always include units to ensure accurate proportionality.

4. Overlooking Cross Multiplication: When solving proportions, students may forget to cross-multiply. This step is essential for finding the value of unknowns correctly.

5. Neglecting Unitary Method: Forgetting to apply the unitary method to solve problems related to proportions can hinder accurate solutions. Ensure consistency in units throughout.

6. Not Verifying Answers: Students might forget to check their solutions back into the original problem. Always verify answers to confirm their correctness in the given context.

Being mindful of these common pitfalls can help students navigate Direct and Inverse Proportions with greater accuracy and understanding.

Tips and Tricks to Solve Chapter 11 - Direct and Inverse Proportions with Ease!

Here are 8 tips and tricks to solve "Chapter 11 - Direct and Inverse Proportions" with ease:

1. Understand the Concept: Grasp the difference between direct and inverse proportions. In direct, one variable increases as the other increases, and in inverse, one decreases as the other increases.

2. Identify the Proportionality Constant: Pay attention to the constant that relates the two variables. It's crucial for setting up accurate proportions.

3. Include Units in Ratios: Always include units when setting up ratios. This helps in maintaining consistency and ensuring correct proportionality.

4. Cross-Multiply Carefully: When dealing with proportions, cross-multiplication is key. Double-check your calculations to avoid errors.

5. Apply Unitary Method: Use the unitary method to solve problems related to proportions. It simplifies calculations and ensures accuracy.

6. Verify Answers: After finding solutions, don't forget to check them back into the original problem. This step ensures the correctness of your answers in the given context.

7. Practice Regularly: Practice solving various problems regularly to reinforce your understanding of direct and inverse proportions. It builds confidence and familiarity.

8. Use Real-Life Examples: Relate problems to real-life situations to enhance your understanding. This makes the concepts more tangible and relatable.

By incorporating these tips, you can approach "Direct and Inverse Proportions" with confidence and tackle problems with ease!

What are the Benefits of Important Questions from Vedantu for Class 8 Maths Chapter 11 - Direct and Inverse Proportions 

Focus on key topics for efficient studying.

Prepares students for exams and reduces anxiety.

Reinforces understanding of fundamental concepts.

Teaches effective time management.

Enables self-assessment and progress tracking.

Strategic approach for higher scores.

Covers a wide range of topics for comprehensive understanding.

Supports exam preparation and boosts confidence.

Reviewing all the crucial questions for Class 8 Maths Chapter 11 - Direct and Inverse Proportions provides students with a solid grasp of the chapter's topics. The extra and important questions for Class 8 Maths Chapter 11 - Direct and Inverse Proportions engage in a concept-focused discussion, encompassing all chapter themes. This question-and-answer method proves time-saving during exam prep, offering an efficient way to revise the chapter and enhance understanding. Practising these important questions streamlines preparation and boosts confidence for the upcoming exams.

FAQs on Important Questions for CBSE Class 8 Maths Chapter 11 - Direct and Inverse Proportions

1. What is the direct proportion?

A mathematical comparison between two numbers in which the ratio of the two numbers equals a fixed value is known as direct proportion. When two ratios are equal, they are in proportion, according to the proportion definition. When two quantities are split in a direct proportion, the ratio between them remains the same. (They divide into equal portions). Daily hours are an example of a directly proportional relationship. We can find other examples of direct proportion in our day to day life.

2. Where can I avail myself of the Solutions of Class 8 Maths Chapter 11?

The solutions are easily available on the Vedantu site. 

Visit the page NCERT Solutions for Class 8 Maths Chapter 11.

The webpage with Vedantu’s solutions for Class 8 Maths Chapter 11 will open.

To download this, click on the Download PDF button and you can view the solutions offline. 

You can browse through the solutions of the other exercises and chapters as well on the Vedantu website and on the Vedantu app at free of cost.

3. What do you mean by inverse proportion?

When one quantity rises, the other decreases in an indirect (or inverse) proportion. The product of the matching amounts remains the same in an inverse proportion. When one number grows while the other drops, the inverse proportion occurs. Adding additional workers to a task, for example, might speed up completion. That means that they're inversely proportional to each other. Practice all the problems related to inverse proportion to learn each topic concerned with inverse proportions. Important questions are easily available on Vedantu. 

4. Is direct proportion always linear?

A linear connection that is exactly proportionate or directly proportional is a specific form of a linear relationship. When one variable equals 0, the second variable has the same value as the first. On a graph, the "origin" would be represented by a straight line. The graph of a proportionate connection is always a straight line since the two variables always change by the same multiple and one cannot observe any bends, curves or open spots. 

5. How do I find out proportionality?

You might write several ratios as fractions, decrease them and then compare them to determine if they are proportionate. Proportional ratios exist when the reduced fractions are all the same. This is one of the most efficient ways to find out the proportionality of comparatively simpler quantities. Practice all of the direct proportion problems to become proficient in each concept of direct proportions.

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Home » 8th Class » Class 8 Maths Notes for (PDF) – Study Material

Class 8 Maths Notes for (PDF) – Study Material

Class 8 Maths Notes are now available for download here. Here you can get Short Notes for Class 8 Maths. If you are a Class 8th student, then you can use the Class 8 Maths Notes PDF to study all the chapters. You can download the Class 8 notes for Maths subject for all chapters here at aglasem.com.

• Class 8 Maths Notes

Here are the class 8 Maths notes . If you are studying Maths then you can easily download Class 8 Maths notes pdf here to learn about the topics. Maths notes and summary are compiled by expert teachers so that you can study easily with them. All the notes are chapter wise. That’s why you can read and understand about each chapter or topic given in Class 8th Maths book with this free study material.

• Rational Numbers
• Linear Equation in One Variable
• Understanding Quadrangles
• Data Handling
• Square and Square Roots
• Comparing Quantities
• Algebraic Expression and Identities
• Mensuration
• Exponents and Powers
• Direct and Inverse Proportions
• Factorisation
• Introduction to Graphs

After notes we have also provided important questions of the Class 8 Maths textbook. You can practice the Maths questions and check your answers from the solutions given after questions. One Class 8 Maths test is also there for your practice.

• Class 8 Notes

Not only can you study all the topics with the Maths notes . These are also the Class 8 Maths summary that help you read the portion quickly. Moreover they help you arrive at the Class 8 Maths solutions to the chapter-wise questions answers. All the notes for Class 8 students, subject-wise, are as follows.

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Class 8 Maths Notes for All Boards

Likewise the 8th class Maths notes here are useful for other boards also. As you know, the different boards for Class 8 in India are CBSE, CISCE, SEBA, BSE Odisha, CGBSE, HBSE, HPBOSE, KSEEB, MSBSHSE, PSEB, RBSE, TBSE, UPMSP, UBSE, BSEAP, BSEB, GBSHSE, GSEB, JAC, JKBOSE, KBPE, MBOSE, MBSE, MPBSE, NBSE, DGE TN, BSE Telangana, BOSEM, WBBSE . Therefore if you are a student of any of these boards, then you can use the Class 8 / Class 8th Maths notes PDF here to complete your curriculum.

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Class 8 Maths NCERT Solutions, Notes, Question Bank and Practice Papers

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User submitted papers, rational numbers, linear equations in one variable, understanding quadrilaterals, practical geometry (deleted), data handling, squares and square roots, cubes and cube roots, comparing quantities, algebraic expressions and identities, visualising solid shapes, mensuration, exponents and powers, direct and inverse proportions, factorisation, introduction to graphs, playing with numbers.

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Case Study Questions for Class 8 Maths Chapter 3 Understanding Quadrilaterals

• Last modified on: 1 year ago
• Reading Time: 3 Minutes

Here we are providing Case Study questions for Class 8 Maths Chapter 3 Understanding Quadrilaterals.

Case Study Questions

Related posts, learning outcomes.

• Convex and Concave Polygons.
• Regular and Irregular Polygons.
• Sum of Measures of the Exterior Angles of a Polygon.
• Kinds of QuadrilateralTrapezium; Kite; Parallelogram.
• Some Special ParallelogramsRhombus; Rectangle; Square.

Important Keywords

• Convex Polygon: Polygons that have any line segment joining any two different points in the interior and have no portions of their diagonals in their exteriors are called convex polygons.
• Concave Polygon: Polygons that have one diagonal outside it are called concave polygons.
• Regular Polygon: A polygon whose all sides, all angles are equal that is which is both equiangular and equilateral are called regular polygon. Example: Square; Equilateral triangle
• Irregular Polygon: Polygon whose all sides are not equal are called Irregular polygon. Example: Rectangle.

Fundamental Facts

• Convex Polygon has each angle either acute or obtuse.
• Concave Polygon has one angle as reflex angle.

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• STUDY MATERIAL FOR CBSE CLASS 8 MATH
• Chapter 1 - Algebraic Expressions and Identities
• Chapter 2 - Comparing Quantities
• Chapter 3 - Cubes and Cube Roots
• Chapter 4 - Data handling
• Chapter 5 - Direct and Inverse Proportions
• Chapter 6 - Exponents and Powers
• Chapter 7 - Factorization
• Chapter 8 - Introduction to Graphs
• Chapter 9 - Mensuration
• Chapter 10 - Playing with Numbers
• Chapter 11 - Practical Geometry
• Chapter 12 - Squares and Square Roots
• Chapter 13 - Visualizing Solid Shapes
• Chapter 14 - Linear Equations in One Variable
• Chapter 15 - Rational Numbers
• Chapter 16 - Understanding Quadrilaterals

• Understanding Quadrilaterals Class 8 Case Study Questions Maths Chapter 3

Last Updated on September 8, 2024 by XAM CONTENT

Hello students, we are providing case study questions for class 8 maths. Case study questions are the new question format that is introduced in CBSE board. The resources for case study questions are very less. So, to help students we have created chapterwise case study questions for class 8 maths. In this article, you will find case study questions for CBSE Class 8 Maths Chapter 3 Understanding Quadrilaterals. It is a part of Case Study Questions for CBSE Class 8 Maths Series.

Table of Contents

Case Study Questions on Understanding Quadrilaterals

There is a trapezium MNOP, angle bisector of ∠M and ∠N meet at point W, and angle bisector of ∠O and ∠P meet at point X on side MN of trapezium MNOP.

By using the figure give the answers to following questions:

Q. 1. What is the value of a? (a) 80° (b) 60° (c) 90° (d) 70°

Ans. Option (b) is correct. Explanation: In Triangle XPO, ∠XPO = 50° (XP is angle bisector of ∠X) ∠XOP = 70° (XO is angle bisector of ∠XPO) ∠XOP + ∠XPO + a = 180° 70° + 50° + a = 180° a = 180°– 120° a = 60°

Q. 2. What is the value of d? (a) 70° (b) 60° (c) 80° (d) 90°

Ans. Option (d) is correct. Explanation: ∠O + ∠N = 180° (sum of adjacent angles of trapezium is 180°)

Also read: Understanding Quadrilaterals Assertion Reason Questions for Class 8

Q. 3. What is the value of c? (a) 90° (b) 70° (c) 50° (d) 80°

Ans. Option (a) is correct. Explanation: ∠P + ∠M = 180° (sum of adjacent angles of trapezium is 180°)

Q. 4. What type of triangle is POX?

Ans. In triangle POX, All angles are less than 90°, therefore it is an acute angle triangle.

Q. 5. What is the value of b?

Ans. In quadrilateral XYWZ, a + b + y +z = 360° c = y = 90° (vertically opposite angles are equal) d = z = 90° (vertically opposite angles are equal) 60° + b + 90°+ 90° = 360° b = 120°

• Direct and Inverse Proportions Class 8 Case Study Questions Maths Chapter 11
• Exponents and Powers Class 8 Case Study Questions Maths Chapter 10
• Mensuration Class 8 Case Study Questions Maths Chapter 9
• Algebraic Expressions and Identities Class 8 Case Study Questions Maths Chapter 8
• Comparing Quantities Class 8 Case Study Questions Maths Chapter 7
• Cube and Cube Roots Class 8 Case Study Questions Maths Chapter 6
• Square and Square Roots Class 8 Case Study Questions Maths Chapter 5
• Data Handling Class 8 Case Study Questions Maths Chapter 4

Linear Equations in One Variable Class 8 Case Study Questions Maths Chapter 2

Rational numbers class 8 case study questions maths chapter 1, download ebooks for cbse class 8 maths understanding quadrilaterals.

• Understanding Quadrilaterals Topicwise Worksheet for CBSE Class 8 Maths

Download eBooks for CBSE Class 8 Maths

• Rational Numbers Topicwise Worksheet for CBSE Class 8 Maths
• Linear Equations in One Variable Worksheet for CBSE Class 8 Maths
• Understanding Quadrilaterals Worksheet for CBSE Class 8 Maths
• Data Handling Worksheet for CBSE Class 8 Maths
• Squares and Square Roots Worksheet for CBSE Class 8 Maths
• Cube and Cube Roots Worksheet for CBSE Class 8 Maths
• Comparing Quantities Worksheet for CBSE Class 8 Maths
• Algebraic Expressions and Identities Worksheet for CBSE Class 8 Maths

Topics from which case study questions may be asked

• Convex and Concave Polygons.
• Regular and Irregular Polygons.
• Sum of Measures of the Exterior Angles of a Polygon.
• Kinds of QuadrilateralTrapezium; Kite; Parallelogram.
• Some Special ParallelogramsRhombus; Rectangle; Square.

Frequently Asked Questions (FAQs) on Understanding Quadrilaterals Case Study

Q1: why understanding quadrilaterals are important.

A1: Understanding quadrilaterals is crucial for building a strong foundation in geometry, enabling real-world applications in design and construction. It enhances problem-solving skills, fosters critical thinking, and prepares students for advanced mathematical concepts and career opportunities.

Q2: What is a quadrilateral?

A2: A quadrilateral is a polygon with four sides and four angles.

Q3: What are the different types of quadrilaterals?

A3: There are various types of quadrilaterals, including squares, rectangles, parallelograms, rhombuses, trapeziums, and kites.

Q4: How do you classify quadrilaterals based on their properties?

A4: Quadrilaterals can be classified based on their properties such as sides, angles, and diagonals. For example: (1) Parallelograms have opposite sides that are equal and parallel. (2) Rhombuses have all four sides equal in length. (3) Rectangles have all angles equal to 90 degrees.

Q5: What is the sum of angles in a quadrilateral?

A5: The sum of angles in any quadrilateral is always 360 degrees.

Q6: Can a quadrilateral have equal sides and angles but still not be a square?

A6: Yes, a rhombus can have all sides equal and opposite angles equal, but its angles need not be right angles, unlike in a square.

Q7: How do you prove that a quadrilateral is a parallelogram?

A7: A quadrilateral can be proved as a parallelogram if its opposite sides are equal and parallel, or if its opposite angles are equal.

Q8: What is the difference between a square and a rhombus?

A8: A square is a type of rhombus with all four sides equal and all angles equal to 90 degrees. However, a rhombus may have all sides equal but not necessarily all angles equal to 90 degrees.

Q9: What do you mean by convex polygon?

A9: Polygons that have any line segment joining any two different points in the interior and have no portions of their diagonals in their exteriors are called convex polygons.

Q10: What do you mean by concave polygon?

A10: Polygons that have one diagonal outside it are called concave polygons.

Q11: What do you mean by regular polygon?

A11: A polygon whose all sides, all angles are equal that is which is both equiangular and equilateral are called regular polygon. Example: Square; Equilateral triangle

Q12: What do you mean by irregular polygon?

A12: Polygon whose all sides are not equal are called Irregular polygon. Example: Rectangle.

Q13: Are there any online resources or tools available for practicing understanding quadrilaterals case study questions?

A13: We provide case study questions for CBSE Class 8 Maths on our  website . Students can visit the website and practice sufficient case study questions and prepare for their exams. If you need more case study questions, then you can visit  Physics Gurukul  website. they are having a large collection of case study questions for all classes.

Q14: What are the important points to note for CBSE Class 8 Maths Understanding Quadrilaterals?

A14: Here are some important points to observe/note (i) Every parallelogram is a trapezium, but every trapezium is not a parallelogram. (ii) Every rectangle, rhombus and square are parallelograms, but every parallelogram is not a rectangle or a rhombus or a square. (iii) Every square is a rectangle, but every rectangle is not a square. (iv) Every square is a rhombus, but every rhombus is not a square

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