lesson 20 homework 4.3 4th grade

EMBARC.Online

Topic outline, grade 4 module 3, multi-digit multiplication and division.

Topic A: Multiplicative Comparison Word Problems

Topic b: multiplication by 10, 100, and 1,000, topic c: multiplication of up to four digits by single-digit numbers.

Topic D: Multiplication Word Problems

Mid-module review, topic e: division of tens and ones with successive remainders, topic f: reasoning with divisibility, topic g: division of thousands, hundreds, tens, and ones, topic h: multiplication of two-digit by two-digit numbers, end-of-module.

If you're seeing this message, it means we're having trouble loading external resources on our website.

If you're behind a web filter, please make sure that the domains *.kastatic.org and *.kasandbox.org are unblocked.

To log in and use all the features of Khan Academy, please enable JavaScript in your browser.

4th grade (Eureka Math/EngageNY)

Unit 1: module 1: place value, rounding, and algorithms for addition and subtraction, unit 2: module 2: unit conversions and problem solving with metric measurement, unit 3: module 3: multi-digit multiplication and division, unit 4: module 4: angle measure and plane figures, unit 5: module 5: fraction equivalence, ordering, and operations, unit 6: module 6: decimal fractions, unit 7: module 7: exploring measurement with multiplication.

The Teacher's Guide-Free Worksheets, SMARTboard templates, and lesson plans for teachers.

McGraw-Hill Reading Wonders

Mcgraw-hill wonders 4th grade resources and printouts.

This is the 2014 and 2017 version.  You can find the 2020 version here.

Copyright ©-The Teacher's Guide 2013-Free worksheets, printouts, lesson plans, SMARTBoard templates, and more.

                    Home             Contact             About Us             Advertise

• Texas Go Math
• Big Ideas Math
• enVision Math
• EngageNY Math
• McGraw Hill My Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
• Privacy Policy

Texas Go Math Grade 4 Lesson 4.3 Answer Key Compare and Order Fractions

Refer to our Texas Go Math Grade 4 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 4 Lesson 4.3 Answer Key Compare and Order Fractions.

Essential Question

How can you order fractions? Answer:

• Step 1: Find the least common denominators. Given a set of fractions with unlike denominators, find the least common denominator (LCD) shared by the fractions. …
• Step 2: Determine the equivalent fractions sharing the LCD. …
• Step 3: Arrange the numerators. …
• Step 4: Rewrite the fractions.

Unlock the Problem

• Underline what you need to find.
• Circle the fractions you will compare.

Jody has equal-size bins for the recycling center. She tilled \(\frac{3}{5}\) of a bin with plastics, \(\frac{1}{12}\) of a bin with paper, and \(\frac{9}{10}\) of a bin with glass. Which bin is the most full? Answer: \(\frac{9}{10}\) Explanation: Make common denominator for all \(\frac{3}{5}\) = \(\frac{36}{60}\) \(\frac{1}{12}\) = \(\frac{5}{60}\) \(\frac{9}{10}\) = \(\frac{54}{60}\)

Math Idea Sometimes it is not reasonable to find the exact location of a point on a number line. Benchmarks can help you find approximate locations.

The fraction the greatest distance from 0 has the greatest value. The fraction with the greatest value is ____________ . So, the bin with ____________ is the most full. Answer:

Mathematical Processes Explain how to write \(\frac{3}{5}\) and \(\frac{9}{10}\) as decimals in hundredths and compare their distances from 0. Answer: \(\frac{3}{5}\) = \(\frac{60}{100}\) \(\frac{9}{10}\) = \(\frac{90}{100}\)

Step 1 Compare each fraction to \(\frac{1}{2}\). List fractions that are less than \(\frac{1}{2}\): ________________ List fractions that are greater than \(\frac{1}{2}\): ________________ The fraction with the least value is ________________. Locate and label \(\frac{1}{3}\) on the number tine above. Answer:

Step 2 Compare \(\frac{7}{10}\) to \(\frac{7}{12}\) and \(\frac{8}{10}\).

Think: \(\frac{7}{10}\) and \(\frac{7}{12}\) have equal numerators. \(\frac{7}{10}\) ___________ \(\frac{7}{12}\) Answer:

Think: \(\frac{7}{10}\) and \(\frac{8}{10}\) have equal denominators. \(\frac{7}{10}\) ___________ \(\frac{8}{10}\) Answer:

Locate and label \(\frac{7}{10}\), \(\frac{7}{12}\), and \(\frac{8}{10}\) on the number line above. The fractions in order from least to greatest are ___________ . So, _____ < _____ < _____ < ______ . Answer:

Mathematical Processes Explain how benchmarks can help you order Answer:

Share and Show

Explanation: Make the common denominator for all \(\frac{3}{10}\)= \(\frac{36}{120}\) \(\frac{11}{12}\)= \(\frac{110}{120}\) \(\frac{5}{8}\) = \(\frac{75}{120}\)

Write the fractions in order from least to greatest.

Lesson 4.3 Problem Set Answer Key Go Math Grade 4 Question 2. \(\frac{1}{4}, \frac{5}{8}, \frac{1}{2}\) Answer: \(\frac{1}{4}, \frac{1}{2}, \frac{5}{8}\) Explanation: Make the common denominator for all \(\frac{1}{4}\) = \(\frac{2}{8}\) \(\frac{5}{8}\) = \(\frac{5}{8}\) \(\frac{1}{2}\) = \(\frac{4}{8}\)

Question 3. \(\frac{3}{5}, \frac{2}{3}, \frac{3}{10}, \frac{4}{5}\) Answer: \(\frac{3}{10},\frac{3}{5}, \frac{2}{3}, \frac{4}{5}\) Explanation: Make the common denominator for all \(\frac{3}{5}\) = \(\frac{18}{30}\) \(\frac{2}{3}\) = \(\frac{20}{30}\) \(\frac{3}{10}\) = \(\frac{9}30}\) \(\frac{4}{5}\) = \(\frac{24}{30}\)

Question 4. \(\frac{3}{4}, \frac{7}{12}, \frac{5}{12}\) Answer: \( \frac{5}{12},\frac{7}{12}, \frac{3}{4}\) Explanation: Make the common denominator for all \(\frac{3}{4}\) = \(\frac{9}{12}\) \(\frac{7}{12}\) = \(\frac{7}{12}\) \(\frac{5}{12}\) = \(\frac{5}{12}\)

H.O.T. Algebra Write a numerator that makes the statement true.

Question 5. \(\frac{1}{2}\) < \(\frac{}{10}\) < \(\frac{4}{5}\) Answer: \(\frac{1}{2}\) < \(\frac{6}{10}\) < \(\frac{4}{5}\) Explanation: Make the common denominator for all \(\frac{1}{2}\) = \(\frac{5}{10}\) \(\frac{5}{10}\) = \(\frac{}{10}\) \(\frac{4}{5}\) = \(\frac{8}{10}\)

Question 6. \(\frac{1}{4}\) < \(\frac{5}{12}\) < \(\frac{}{6}\) Answer: \(\frac{1}{4}\) < \(\frac{5}{12}\) < \(\frac{1}{6}\) Explanation: Make the common denominator for all \(\frac{1}{4}\) = \(\frac{3}{12}\) \(\frac{5}{12}\) = \(\frac{5}{12}\) \(\frac{}{6}\) = \(\frac{6}{12}\) = \(\frac{1}{6}\)

Go Math Lesson 4.3 4th Grade Homework Answer Key Question 7. \(\frac{}{8}\) < \(\frac{3}{4}\) < \(\frac{7}{8}\) Answer: \(\frac{5}{8}\) < \(\frac{3}{4}\) < \(\frac{7}{8}\) Explanation: Make the common denominator for all \(\frac{}{8}\) = \(\frac{5}{8}\) \(\frac{3}{4}\) = \(\frac{6}{8}\) \(\frac{7}{8}\) = \(\frac{7}{8}\)

Problem Solving

a. What do you need to find? Answer:

b. What information do you need to solve the problem? Answer:

c. What information is not necessary? Answer:

d. How will you solve the problem? Answer:

e. Show the steps to solve the problem. Answer:

f. Complete the sentences. The runner who finished first is _________ . The runner who finished second is _________ . The runner who finished third is __________ . Answer:

Question 9. Multi-Step Alma used 3 beads to make a necklace. The lengths of the beads are \(\frac{5}{6}\) inch, \(\frac{5}{12}\) inch, and \(\frac{1}{3}\) inch. What are the lengths in order from shortest to longest? Answer: \(\frac{1}{3}\) , \(\frac{5}{12}\), \(\frac{5}{6}\) Explanation: Make the common denominator for all \(\frac{5}{6}\) = \(\frac{10}{12}\) \(\frac{5}{12}\) = \(\frac{5}{12}\) \(\frac{1}{3}\) = \(\frac{4}{12}\)

Question 10. H.O.T. Apply Portia lias done \(\frac{3}{7}\) of her English homework, \(\frac{6}{7}\) of her math homework, and \(\frac{6}{11}\) of her geography homework. Which subject is most complete? Which subject does she have the most left to do? Answer: Math subject is most completed. English subject most left . Explanation: Make the common denominator for all \(\frac{3}{7}\) = \(\frac{33}{77}\) \(\frac{6}{7}\) = \(\frac{66}{77}\) \(\frac{6}{11}\) = \(\frac{42}{77}\)

Daily Assessment Task

Fill in the bubble completely to show your answer.

Question 13. Multi-Step The three puppies at the animal shelter weighed \(\frac{2}{3}\) pound, \(\frac{5}{6}\) pound, and \(\frac{7}{12}\) pound. Compare \(\frac{2}{3}\), \(\frac{5}{6}\), and \(\frac{7}{12}\). Which shows the fractions written in order from least to greatest? (A) \(\frac{2}{3}\) < \(\frac{7}{12}\) < \(\frac{5}{6}\) (B) \(\frac{2}{3}\) < \(\frac{5}{6}\) < \(\frac{7}{12}\) (C) \(\frac{7}{12}\) < \(\frac{5}{6}\) < \(\frac{2}{3}\) (D) \(\frac{7}{12}\) < \(\frac{2}{3}\) < \(\frac{5}{6}\) Answer: \(\frac{7}{12}\) < \(\frac{2}{3}\) < \(\frac{5}{6}\) Make the common denominator for all \(\frac{2}{3}\) = \(\frac{8}{12}\) \(\frac{5}{6}\) = \(\frac{10}{12}\) \(\frac{7}{12}\) = \(\frac{7}{12}\)

TEXAS Test Prep

Question 14. A recipe for Trail Mix includes \(\frac{3}{10}\) cup of sunflower seeds, \(\frac{1}{2}\) cup of raisins, and \(\frac{3}{8}\) cup of granola. Which list shows the amounts from least to greatest? (A) \(\frac{1}{2}\)cup, \(\frac{3}{8}\)cup, \(\frac{3}{10}\)cup (B) \(\frac{3}{8}\)cup, \(\frac{3}{10}\)cup, \(\frac{1}{2}\)cup (C) \(\frac{3}{10}\)cup, \(\frac{3}{8}\)cup, \(\frac{1}{2}\)cup (D) \(\frac{3}{10}\)cup, \(\frac{1}{2}\)cup, \(\frac{3}{8}\)cup Answer: \(\frac{2}{8},\frac{2}{6}, \frac{2}{4} \) Explanation: (C)   \(\frac{3}{10}\)cup, \(\frac{3}{8}\)cup, \(\frac{1}{2}\)cup Make the common denominator for all \(\frac{3}{10}\) = \(\frac{12}{40}\) \(\frac{1}{2}\) = \(\frac{20}{40}\) \(\frac{3}{8}\) = \(\frac{15}{40}\)

Texas Go Math Grade 4 Lesson 4.3 Homework and Practice Answer Key

Question 1. \(\frac{2}{8}, \frac{2}{4}, \frac{2}{6}\) Answer: \(\frac{2}{8},\frac{2}{6}, \frac{2}{4} \) Explanation: Make the common denominator for all \(\frac{2}{8}\) = \(\frac{6}{24}\) \(\frac{2}{4}\) = \(\frac{12}{24}\) \(\frac{2}{6}\) = \(\frac{8}{24}\)

Question 2. \(\frac{2}{5}, \frac{1}{3}, \frac{5}{6}\) Answer: \(\frac{1}{3},\frac{2}{5}, \frac{5}{6}\) Explanation: Make the common denominator for all \(\frac{2}{5}\) = \(\frac{12}{30}\) \(\frac{1}{3}\) = \(\frac{10}{30}\) \(\frac{5}{6}\) = \(\frac{25}{30}\)

Write a numerator that makes the statement true.

Question 3. \(\frac{7}{12}\) < \(\frac{}{3}\) < \(\frac{3}{4}\) Answer: \(\frac{7}{12}\) < \(\frac{2}{3}\) < \(\frac{3}{4}\) Explanation: Make the common denominator for all \(\frac{7}{12}\) = \(\frac{7}{12}\) \(\frac{}{3}\) = \(\frac{8}{12}\)  = latex]\frac{2}{3}[/latex] \(\frac{3}{4}\) = \(\frac{9}{12}\)

Go Math Grade 4 Lesson 4.3 Practice and Homework Answer Key Question 4. \(\frac{}{10}\) < \(\frac{9}{15}\) < \(\frac{4}{5}\) Answer: \(\frac{5}{10}\) < \(\frac{9}{15}\) < \(\frac{4}{5}\) Explanation: Make the common denominator for all \(\frac{}{10}\) = \(\frac{15}{30}\) =\(\frac{5}{10}\) \(\frac{9}{15}\) = \(\frac{18}{30}\) \(\frac{4}{5}\) = \(\frac{24}{30}\)

Question 6. Walt’s friend Paul also ran in the race. Who finished first, Walt or Paul? Answer: Paul Finished first. Explanation: Walt – \(\frac{4}{5}\) = 0.8 hour = 48 min Dalia –\(\frac{2}{3}\) = 0.66 hour =39.6 min Kyra – \(\frac{5}{6}\) = 0.83 hour = 49.8 min Paul- \(\frac{3}{10}\) = 0.3 hour = 18 min

Lesson Check

Question 7. A recipe for ice cream includes \(\frac{3}{4}\) cup milk, \(\frac{1}{3}\) cup cream, and \(\frac{1}{8}\) cup sugar. Which shows the amounts from least to greatest? (A) \(\frac{1}{3}\)cup, \(\frac{3}{4}\)cup, \(\frac{1}{8}\)cup (B) \(\frac{1}{8}\)cup, \(\frac{3}{4}\)cup, \(\frac{1}{8}\)cup (C) \(\frac{1}{3}\)cup, \(\frac{3}{4}\)cup, \(\frac{1}{8}\)cup (D) \(\frac{1}{8}\)cup, \(\frac{1}{3}\)cup,\(\frac{3}{4}\)cup Answer: D Explanation: \(\frac{1}{3}\) = 0.33 \(\frac{3}{4}\) = 0.75 \(\frac{1}{8}\) =  0.12

Question 8. Order the fractions from least to greatest. \(\frac{4}{5}, \frac{1}{3}, \frac{7}{10}, \frac{3}{5}\) (A) \(\frac{1}{3}\) < \(\frac{3}{5}\) < \(\frac{7}{10}\) < \(\frac{4}{5}\) (B) \(\frac{3}{5}\) < \(\frac{1}{3}\) < \(\frac{4}{5}\) < \(\frac{7}{10}\) (C) \(\frac{7}{10}\) < \(\frac{3}{5}\) < \(\frac{1}{3}\) < \(\frac{4}{5}\) (D) \(\frac{4}{5}\) < \(\frac{7}{10}\) < \(\frac{1}{3}\) < \(\frac{3}{5}\) Answer: Explanation: \(\frac{4}{5}\) =0.8 \(\frac{7}{10}\) =0.7 \(\frac{1}{3}\) = 0.33 \(\frac{3}{5}\) = 0.6 Based on above decimal value , below is the order from least to greatest \(\frac{1}{3}\) < \(\frac{3}{5}\) < \(\frac{7}{10}\) < \(\frac{4}{5}\)

Question 9. Order the fractions from least to greatest. \(\frac{2}{3}, \frac{1}{4}, \frac{5}{12}, \frac{3}{4}\) (A) \(\frac{1}{4}, \frac{2}{3}, \frac{5}{12}, \frac{3}{4}\) (B) \(\frac{3}{4}, \frac{5}{12}, \frac{2}{3}, \frac{1}{4}\) (C) \(\frac{1}{4}, \frac{5}{12}, \frac{2}{3}, \frac{3}{4}\) (D) \(\frac{1}{4}, \frac{5}{12}, \frac{3}{4}, \frac{2}{3}\) Answer: (D) \(\frac{1}{4}, \frac{5}{12}, \frac{3}{4}, \frac{2}{3}\) Explanation: \(\frac{2}{3}\) =0.66 \(\frac{1}{4}\) =0.25 \(\frac{5}{12}\) = 0.41 \(\frac{3}{4}\) = 0.75 below is the Order the fractions from least to greatest. \(\frac{1}{4}, \frac{5}{12}, \frac{3}{4}, \frac{2}{3}\)

Question 10. Three potatoes weigh \(\frac{1}{4}\) pound, \(\frac{5}{8}\) pound, and \(\frac{1}{2}\) pound. Which shows the weights from least to greatest? (A) \(\frac{1}{4}\)pound, \(\frac{5}{8}\)pound, \(\frac{1}{2}\)pound (B) \(\frac{1}{2}\)pound, \(\frac{1}{4}\)pound, \(\frac{5}{8}\)pound (C) \(\frac{5}{8}\)pound, \(\frac{1}{2}\)pound, \(\frac{1}{4}\)pound (D) \(\frac{1}{4}\)pound, \(\frac{1}{2}\)pound, \(\frac{5}{8}\)pound Answer: (D) \(\frac{1}{4}\)pound, \(\frac{1}{2}\)pound, \(\frac{5}{8}\)pound Explanation: \(\frac{1}{4}\) = 0.25 \(\frac{5}{8}\) = 0.625 \(\frac{1}{2}\) = 0.5 Based on the above decimal values of weights, below is the order from least to greatest \(\frac{1}{4}\)pound, \(\frac{1}{2}\)pound, \(\frac{5}{8}\)pound

My Homework Lesson 4.3 Compare and Order Fractions Answer Key Question 11. Multi-Step Selma used stones to outline her garden. The lengths of the stones are \(\frac{1}{3}\)foot, \(\frac{7}{12}\) foot, and \(\frac{3}{4}\) foot. What are the lengths in order from shortest to longest? (A) \(\frac{7}{12}\)foot, \(\frac{3}{4}\)foot, \(\frac{1}{3}\)foot (B) \(\frac{1}{3}\)foot, \(\frac{7}{12}\)foot, \(\frac{3}{4}\)foot (C) \(\frac{3}{4}\)foot, \(\frac{7}{12}\)foot, \(\frac{1}{3}\)foot (D) \(\frac{7}{12}\)foot, \(\frac{1}{3}\)foot, \(\frac{3}{4}\)foot Answer: (B) \(\frac{1}{3}\)foot, \(\frac{7}{12}\)foot, \(\frac{3}{4}\)foot Explanation: \(\frac{7}{12}\) =0.58 \(\frac{3}{4}\) = 0.75 \(\frac{1}{3}\) = 0.33 Based on above decimal values of lengths, below is the order from shortest to longest \(\frac{1}{3}\)foot, \(\frac{7}{12}\)foot, \(\frac{3}{4}\)foot

Question 12. Multi-Step Ms. Mohan bought cheese for a recipe. She bought \(\frac{5}{6}\) pound of cheddar cheese, \(\frac{1}{4}\) pound of Swiss cheese, and \(\frac{3}{8}\) pound of American cheese. What are the amounts in order from least to greatest? (A) \(\frac{5}{6}\)pound, \(\frac{1}{4}\)pound, \(\frac{3}{8}\)pound (B) \(\frac{3}{8}\)pound, \(\frac{5}{6}\)pound, \(\frac{1}{4}\)pound (C) \(\frac{1}{4}\)pound, \(\frac{3}{8}\)pound, \(\frac{5}{6}\)pound (D) \(\frac{3}{8}\)pound, \(\frac{1}{4}\)pound, \(\frac{5}{6}\)pound Answer: (C) \(\frac{1}{4}\)pound, \(\frac{3}{8}\)pound, \(\frac{5}{6}\)pound Explanation: \(\frac{5}{6}\)= 0.83 \(\frac{1}{4}\) = 0.25 \(\frac{3}{8}\) = 0.37 Based on above decimal values, below is the order from least to greatest \(\frac{1}{4}\)pound, \(\frac{3}{8}\)pound, \(\frac{5}{6}\)pound

Share this:

Leave a comment cancel reply.

You must be logged in to post a comment.

Multiple operations Math worksheets plus and minus from 1 to 20 for Seasonal Fun

Description

Multiple operations worksheets are a set of educational resources designed to help students practice addition and subtraction operations with numbers ranging from 1 to 20.

Multiple operations worksheets can be used by teachers in classrooms as part of their lesson plans or by parents who want to supplement their children's learning at home. These worksheets can help students develop their math skills and improve their problem-solving abilities while having fun.

♥♥♥ Follow Me To Be The First To Hear About FREEBIES And Updates ♥♥♥

Thank You For Shopping By My Store.

Your feedback helps me to make the most valuable products for your classroom.

THIRD GRADE Math Additions from 0 up to 100 regrouping worksheets

Questions & Answers

Heroes book.

• We're hiring
• Help & FAQ
• Privacy policy
• Student privacy
• Terms of service
• Tell us what you think

• Texas Go Math
• Big Ideas Math
• Engageny Math
• McGraw Hill My Math
• enVision Math
• 180 Days of Math
• Math in Focus Answer Key
• Math Expressions Answer Key
• Privacy Policy

Eureka Math Grade 4 Module 3 Lesson 9 Answer Key

Engage ny eureka math 4th grade module 3 lesson 9 answer key, eureka math grade 4 module 3 lesson 9 problem set answer key.

Explanation: In standard algorithm we add same time of multiplying as 1 251 X 3 753 , here 3 X 1 ones = 3 ones then 3 x 5 tens = 15 tens we write 5 at tens place and take 1 to hundred place and 3 X 2 hundreds = 6 hundreds, now adding 1 hundred to 6 hundreds we get 7 hundreds , so 3 X 251 = 753.

Explanation: In standard algorithm we add same time of multiplying as 1, 3 135 X 6 810 , here 6 X 5 ones = 30 ones, we write 0 at ones place and take 3 to tens places then 6 x 3 tens = 18 tens + 3 tens = 21 tens, we write 1 at tens place and take 2 to hundred place and 6 X 1 hundred = 6 hundreds, now adding 2 hundreds to 6 hundreds we get 8 hundreds , so 6 X 135 = 810.

Explanation: In standard algorithm we add same time of multiplying as  3 304 X 9 2,736 ,here 9 X 4 ones = 36 ones, we write 6 at ones place and take 3 to tens places then 9 x 0 ten = 0 ten + 3 tens = 3 tens, 9 X 3 hundreds = 27 hundreds, now we write 7 at hundreds place and 2 at thousands place as shown above, So 9 X 304 = 2,736.    

Explanation: In standard algorithm we add same time of multiplying as 2 405 X 4 1,620 ,here 4 X 5 ones = 20 ones, we write 0 at ones place and take 2 to tens places then 4 x 0 ten = 0 ten + 2 tens = 2 tens, 4 X 4 hundreds = 16 hundreds, now we write 6 at hundreds place and 1 at thousand place as shown above, So 4 X 405 = 1,620.

Explanation: In standard algorithm we add same time of multiplying as 3 316 X 5 1,580 ,here 5 X 6 ones = 30 ones, we write 0 at ones place and take 3 to tens places then 5 x 1 ten = 5 tens + 3 tens = 8 tens, 5 X 3 hundreds = 15 hundreds, now we write 5 at hundreds place and 1 at thousand place as shown above, So 5 X 316 = 1,580.

Explanation: In standard algorithm we add same time of multiplying as 5,1 392 X 6 2,352 ,here 6 X 2 ones = 12 ones, we write 2 at ones place and take 1 to tens places then 6 x 9 tens = 54 tens + 1 tens = 55 tens, we write 5 at tens place and take another 5 to hundreds place, 6 X 3 hundreds = 18 hundreds,18 hundreds + 5 hundreds = 23 hundreds now we write 3 at hundreds place and 2 at thousands place as shown above, So 6 X 392 = 2,352.

Question 3. The product of 7 and 86 is ________. Answer: The product of 7 and 86 is 602,

Explanation: Give to find the product of 7 and 86 is 4 86 X 7 602 first we multiply 7 with 6 ones = 42 ones we write 2 at ones place and take 4 to tens place now 7 X 8 = 56 tens adding 4 tens we get 60 tens, So 7 X 86 = 602.

Question 4. 9 times as many as 457 is _________. Answer: 9 times as many as 457 is 4,113,

Explanation: Given to find 9 times as many as 457 is 6 457 X 9 4,113 ,here 9 X 7 ones = 63 ones, we write 3 at ones place and take 6 to tens places then 9 x 5 tens = 45 tens + 6 tens = 51 tens, we write 1 at tens place and take 5 to hundreds place, 9 X 4 hundreds = 36 hundreds, 36 hundreds + 5 hundreds = 41 hundreds now we write 1 at hundred place and 4 at thousands place as shown above, So 9 X 457 = 4,113.

Explanation: Given Jashawn wants to make 5 airplane propellers. He needs 18 centimeters of wood for each propeller. So number of centimeters of wood will he use is 5 X 18 cms = 4 18 X 5 90 here first we multiply 5 X 8 ones = 40 ones, we write 0 at ones place and take 4 to tens place then 5 X 1 ten = 5 tens+ 4 tens = 9 tens, So 5 X 18 = 90 centimeters, therefore, Jashawn needs 90 centimeters of wood to make 5 airplane propellers.

Question 6. One game system costs $238. How much will 4 game systems cost? Answer: 4 game systems will cost $952,

Explanation: Given one game system costs $238. So for 4 game systems it will cost 4 X $238 =  1, 3 $238 X  4 952 here first we multiply 4 X 8 ones = 32 ones, we write 2 at ones place and take 3 to tens places then 4 x 3 tens = 12 tens + 3 tens = 15 tens, we write 5 at tens place and take 1 to hundred place, 4 X 2 hundreds = 8 hundreds, now 8 hundreds + 1 hundred = 9 hundreds, So 5 X $238 = 952, therefore 4 game systems will cost $952.

Explanation: Given a small bag of chips weighs 48 grams. A large bag of chips weighs three times as much as the small bag means 3 X 48 grams= 2 48 X 3 144 here first we multiply 3 X 8 ones = 24 ones, we write 4 at ones place and take 2 to tens place then 3 X 4 ten = 12 tens+ 2 tens = 14 tens, we write 14 tens as 4 at tens place and 1 at hundreds place, So 3 X 48 grams = 144 grams, Now 7 large bags of chips weigh 7 X 144 grams =  3,2 144 X 7 1,008 here first we multiply 7 X 4 ones = 28 ones, we write 8 at ones place and take 2 to tens place then 7 X 4 ten = 28 tens+ 2 tens = 30 tens, we write 30 tens as 0 at tens place and other 3 at hundreds place,now 7 X 1 hundred = 7 hundred, 7 hundred + 3 hundreds = 10 hundreds we write 0 at hundreds place at 1 at thousands place, So 7 X 144 = 1,008 grams, therefore, 7 large bags of chips weigh 1,008 grams.

Eureka Math Grade 4 Module 3 Lesson 9 Exit Ticket Answer Key

Question 2. Morgan is 23 years old. Her grandfather is 4 times as old. How old is her grandfather? Answer: Morgan’s grandfather is 92 years old,

Explanation: Given Morgan is 23 years old and her grandfather is 4 times as old. So Morgan’s grandfather’s is 4 X 23 years = 1 23 X 4 92, here 4 X 3 ones = 12 ones, we write 2 at ones place and take 1 to tens places then 4 x 2 tens = 8 tens, 8 tens + 1 ten = 9 tens, So Morgan’s grandfather is 92 years old.

Eureka Math Grade 4 Module 3 Lesson 9 Homework Answer Key

Explanation: Given expression as 2 X 46 = Partial Products 46 X 2   12 +80 92 , Here we first write multiplication of 2 X 6 ones, then 2 X 4 tens then add as shown above 12 + 80 = 92, In standard algorithm we add same time of multiplying as 1 46 X 2 92 , here 2 X 6 ones= 12 ones we write 2 at ones place and take 1 at tens place then 2 x 4 at tens place = 8 tens add 1 ten to 8 tens we get 9 tens so 2 X 46 = 92.

Explanation: In standard algorithm we add same time of multiplying as 1 232 X 4 928 , here 4 X 2 ones = 8 ones then 4 x 3 tens = 12 tens we write 2 at tens place and take 1 to hundred place and 4 X 2 hundreds = 8 hundreds, now adding 1 hundred to 8 hundreds we get 9 hundreds , so 4 X 232 = 928.

Explanation: In standard algorithm we add same time of multiplying as 1 440 X 3 1,320 ,here 3 X 0 ones = 0 ones, we write 0 at ones place, 3 x 4 tens = 12 tens we write 2 at tens place and take 1 at hundreds place, 3 X 4 hundreds = 12 hundreds, 12 hundreds + 1 hundred = 13 hundreds ,now we write 3 at hundreds place and 1 at thousand place as shown above, So 3 X 440 = 1,320.

Question 3. What is the product of 8 and 54? Answer: The product of 8 and 54 is 432,

Explanation: Give to find the product of 8 and 54 is 3 54 X 8 432 first we multiply 8 with 4 ones = 32 ones we write 2 at ones place and take 3 to tens place now 8 X 5 = 40 tens adding 3 tens we get 43 tens, So 8 X 54 = 432.

Question 4. Isabel earned 350 points while she was playing Blasting Robot. Isabel’s mom earned 3 times as many points as Isabel. How many points did Isabel’s mom earn? Answer: Isabel’s mom earn 1050 points,

Explanation: Given Isabel earned 350 points while she was playing Blasting Robot. Isabel’s mom earned 3 times as many points as Isabel. So  points did Isabel’s mom earn is 3 X 350 = 1 350 X 3 1050, first we multiply 3 with 0 ones = 0 ones , 3 X 5 = 15 tens we write 15 tens as 5 at tens place and 1 at hundreds place and 3 X 3 = 9 hundreds + 1 hundred = 10 hundreds we write 10 hundreds as 0 at hundreds place and 1 at thousands place, So 3 X 350 = 1050. Therefore, Isabel’s mom earn 1050 points.

Question 5. To get enough money to go on a field trip, every student in a club has to raise $53 by selling chocolate bars. There are 9 students in the club. How much money does the club need to raise to go on the field trip? Answer: The club needs to raise $477 to go on the field trip,

Explanation: Given to get enough money to go on a field trip, every student in a club has to raise $53 by selling chocolate bars. There are 9 students in the club. So money does the club need to raise to go on the field trip is 9 X $53 = 2 $53 X 9 $477 first we multiply 9 with 3 ones = 27 ones , we write 7 at ones place and 2 at tens place, 9 X 5 tens= 45 tens, 45 tens + 2 tens = 47 tens we write 47 tens as 7 at tens place and 4 at hundreds place so 9 X $53 = $477, therefore,the club needs to raise $477 to go on the field trip.

Question 6. Mr. Meyers wants to order 4 tablets for his classroom. Each tablet costs $329. How much will all four tablets cost? Answer: Total cost for all four tablets are $1,316,

Explanation: Given Mr. Meyers wants to order 4 tablets for his classroom. Each tablet costs $329. So total cost for four tablets are 4 X $329 = 1,3 $329 X 4 $ 1,316 first we multiply 4 with 9 ones = 36 ones , we write 6 at ones place and 3 at tens place, 4 X 2 tens= 8 tens, 8 tens + 3 tens = 11 tens we write 11 tens as 1 at tens place and 1 at hundreds place, Now 4 X 3 hundreds = 12 hundreds, 12 hundreds + 1 hundred = 13 hundreds, we write 3 at hundreds place and 1 at thousands place, So 4 X $329 = $1,316.

Question 7. Amaya read 64 pages last week. Amaya’s older brother, Rogelio, read twice as many pages in the same amount of time. Their big sister, Elianna, is in high school and read 4 times as many pages as Rogelio did. How many pages did Elianna read last week? Answer: Elianna read 512 pages last week,

Explanation: Given Amaya read 64 pages last week. Amaya’s older brother, Rogelio, read twice as many pages in the same amount of time. So Rogelio reads 2 X 64 pages = 64 X 2 128 2 X 4 ones = 8  and 2 X 6 tens= 120, So 2 X 64 = 8 + 120 = 128, So Rogelio reads 128 pages, Their big sister, Elianna, is in high school and read 4 times as many pages as Rogelio did. So number of pages did Elianna read last week are 4 X 128 pages= 1, 3 128 x 4 512 here we first we multiply 4 with 8 ones = 32 ones , we write 2 at ones place and 3 at tens place, 4 X 2 tens= 8 tens, 8 tens + 3 tens = 11 tens we write 11 tens as 1 at tens place and 1 at hundreds place and 4 X 1 hundred = 4 hundreds, 4 hundreds +1 hundred = 5 hundreds, So 4 X 128 pages = 512 pages, therefore, Elianna read 512 pages last week.

Leave a Comment Cancel Reply

You must be logged in to post a comment.