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How do I fix a "Subscripted assignment dimension mismatch."
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Subscripted assignment dimension mismatch error in Matlab
I get the next error executing this command in Matlab:
Anyone could help me to solve it?
2 Answers 2
There seems to be 3 problems with your code.
First, the command [X, Y] = meshgrid(x_lim, y_lim) creates two 21x41 matrices and saves them to X and Y . So, the second line of your code ( [x(1), x(2)]= meshgrid(x_lim, y_lim); ) is attempting to insert a 21x41 matrix into the first element of x , and a 21x41 matrix into the second element of x . The reason that this does not work is that the each element of the matrix x can only fit 1 element. In other words, x(1) can only fit a 1x1 matrix. To fix this, replace x(1) with X and x(2) with Y . This way, the two 21x41 matrices are saved to their own variables.
Second, note that exp() is a function, and not a variable. So, the fourth line of your function should have exp(-(X+Y)) instead of exp^(-(X+Y)) .
Third, I believe you are trying to do element-wise operations in that same line. Instead, the code specifies matrix multiplication. To specify element-wise operarations, use .* and .^ . So, the fourth line of your code should be: z = (-exp(-(X + Y))).*((sin(3*X)).^2).*((sin(3*Y)).^2);
So, your edited code should look like this now:
- Your answer is surely better and precise than mine! +1. – il_raffa Commented Oct 24, 2015 at 20:14
There are some errors in your script:
- evalaution of meshgrid : the output are 2 matrices while you specifying x(1) and x(2) define 2 scalars
- evaluation of z : exp does not require ^ it is "already" the exponential; also, since you are working with matrices (generated by meshgrid ) all the operand have to be preceded by . (a dot) in order they are applied to each element of the matrices
This is the updated code.
Hope this helps.
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Subscripted assignment dimension mismatch for table variable
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In this case, 'A' has size 2x3, that is, 2 rows and 3 columns. The vector 'B' has size 1x4, 1 row and 4 columns. The assignment statement attempts to replace the second row of 'A' with the row vector 'B', but this is not possible because 'B' has 4 columns, and 'A' only has 3 columns.
For the case where you are assigning values for every pairwise combination, here are a couple of the ways you can do it: Break up the assignment into 3 steps, one for each plane in the third dimension: new_img(rows,cols,1) = curMean(1); %# Assignment for the first plane. new_img(rows,cols,2) = curMean(2); %# Assignment for the second plane.
watermarked_row = reshape (transpose (watermarked), 1, numel (watermarked)); EDITED: And together with Sean de's addition: If you image is a [Width x Height x 3] 3D array, convert it to a grey scale at first: Theme. Copy. watermarked = rgb2gray (watermarked); Or operate on a single color channel only, e.g. red: Theme.
Subscripted assignment dimension mismatch.. Learn more about matlab error
Learn more about subscripted assignment dimension mismatch., subscripted assignment dimension mismatch, subscripted assignment dimension mismatch for loop . Here is the code that I'm getting the error: for z=1:length(X) V(z)=[X(z):Y]; end where X is a 1x81 matrix and Y is an integer ... Find the treasures in MATLAB Central and discover how the ...
Subscripted assignment dimension mismatch. Learn more about subscripted assignment dimension mismatch Dear All, I have recently upgraded to R2016b (from R2013b).
Subscripted assignment dimension mismatch. Follow 1 view (last 30 days) Show older comments. ... MATLAB Language Fundamentals Loops and Conditional Statements. Find more on Loops and Conditional Statements in Help Center and File Exchange. Tags assignment mismatch; Community Treasure Hunt.
" Subscripted assignment dimension mismatch." Follow 12 views (last 30 days) Show older comments. ... When Matlab stops at the error, check the used indices. In other words: Learn to use the debugger. It is the best friend of the programmer - even better than this forum.
Many thanks Thorsten for the answer. Seems your code is working, results are stored in 3d matrix of dimension 143 x 44 x 513. I am trying to convert this to normal 2D array to check the data.
Subscripted assignment dimension mismatch. Learn more about 3d, matrix, array, segmentation, error, dimension, image processing, 2d ... MATLAB Data Import and Analysis Data Import and Export Workspace Variables and MAT-Files. Find more on Workspace Variables and MAT-Files in Help Center and File Exchange.
How do I fix a "Subscripted assignment... Learn more about indexing
Subscripted assignment dimension mismatch.. Learn more about image processing MATLAB
%This is a vector of the dyad numbers to analyze Ndya = {'0115','0126','0132','0162','0181','0194','0206','0226','0241','0252','0254','0255','0259','0261','0268 ...
If you're looping through both dimensions, you don't need the sizes, you're only ever handling scalars. You can also omit the . in pretty much all of those operators since you're not even dealing with matrices. - scenia
Even if your data is a vector size will return 2 values unless you specify a dimension. Theme. Copy. size1 = size (ErrorProb_OrthTr_Gray3Orth1); this will return 1 4916, now if you use a vector for indexing only the first entry will be considered: Theme. Copy. AllErrProb (1:size1)= ErrorProb_OrthTr_Gray3Orth1 (:);
Subscripted assignment dimension mismatch.. Learn more about subscripted assignment dimension mismatch . Hey guys, I'm pretty new to Matlab so please bear with me :) I wrote the following code ===== Result2 = zeros(1, 3... Skip to content. Toggle Main Navigation. Sign In to Your MathWorks Account; My Account ...
Subscripted assignment dimension mismatch. Learn more about matrices
1. There seems to be 3 problems with your code. First, the command [X, Y] = meshgrid(x_lim, y_lim) creates two 21x41 matrices and saves them to X and Y. So, the second line of your code ( [x(1), x(2)]= meshgrid(x_lim, y_lim);) is attempting to insert a 21x41 matrix into the first element of x, and a 21x41 matrix into the second element of x ...
Note the right-hand side of those assignments. Normally, if the LHS is a parenthesis subscript expression, the RHS needs to be the same type, a table in this case.